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Trigonometric Integrals

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1

In a physics problem modeling wave interference, the intensity pattern is given by the integral involving powers of sine and cosine. Determine the indefinite integral: sin4(3x)cos2(3x)dx\int \sin^4(3x) \cos^2(3x) \, dx.

A.x16sin(12x)96sin3(6x)144+C\frac{x}{16} - \frac{\sin(12x)}{96} - \frac{\sin^3(6x)}{144} + C
B.x16sin(6x)48sin(12x)192+sin3(6x)72+C\frac{x}{16} - \frac{\sin(6x)}{48} - \frac{\sin(12x)}{192} + \frac{\sin^3(6x)}{72} + C
C.x16sin(12x)192sin3(6x)144+C\frac{x}{16} - \frac{\sin(12x)}{192} - \frac{\sin^3(6x)}{144} + C
D.3x16sin(12x)64sin3(6x)48+C\frac{3x}{16} - \frac{\sin(12x)}{64} - \frac{\sin^3(6x)}{48} + C
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2

Determine the antiderivative: sin2xcos3xdx\int \sin^2 x \cos^3 x \, dx.

A.14cos4x16cos6x+C\frac{1}{4}\cos^4 x - \frac{1}{6}\cos^6 x + C
B.13sin3x15sin5x+C\frac{1}{3}\sin^3 x - \frac{1}{5}\sin^5 x + C
C.18x132sin4x+C\frac{1}{8}x - \frac{1}{32}\sin 4x + C
D.13sin3x13sin5x+C\frac{1}{3}\sin^3 x - \frac{1}{3}\sin^5 x + C
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3

Evaluate the integral sin3xcos2xdx\int \sin^3 x \cos^2 x \, dx, which arises in the analysis of rotational motion.

A.13cos3x15cos5x+C\frac{1}{3}\cos^3 x - \frac{1}{5}\cos^5 x + C
B.13sin3x15sin5x+C\frac{1}{3}\sin^3 x - \frac{1}{5}\sin^5 x + C
C.15cos5x13cos3x+C\frac{1}{5}\cos^5 x - \frac{1}{3}\cos^3 x + C
D.13cos3x12cos5x+C\frac{1}{3}\cos^3 x - \frac{1}{2}\cos^5 x + C
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