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Advanced Substitution

10 practice questionsCalculus IIStep-by-step solutions

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1

Evaluate the indefinite integral ∫x51−x2 dx\int x^5 \sqrt{1 - x^2} \, dx.

A.−13(1−x2)3/2+25(1−x2)5/2−17(1−x2)7/2+C-\frac{1}{3}(1-x^2)^{3/2} + \frac{2}{5}(1-x^2)^{5/2} - \frac{1}{7}(1-x^2)^{7/2} + C
B.13(1−x2)3/2−25(1−x2)5/2+17(1−x2)7/2+C\frac{1}{3}(1-x^2)^{3/2} - \frac{2}{5}(1-x^2)^{5/2} + \frac{1}{7}(1-x^2)^{7/2} + C
C.−23(1−x2)3/2+45(1−x2)5/2−27(1−x2)7/2+C-\frac{2}{3}(1-x^2)^{3/2} + \frac{4}{5}(1-x^2)^{5/2} - \frac{2}{7}(1-x^2)^{7/2} + C
D.−13(1−x2)3/2+15(1−x2)5/2+C-\frac{1}{3}(1-x^2)^{3/2} + \frac{1}{5}(1-x^2)^{5/2} + C
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2

Evaluate ∫dx2x−x2\int \frac{dx}{\sqrt{2x - x^2}}.

A.arcsin⁡(2x−1)+C\arcsin(2x-1) + C
B.arctan⁡(x−1)+C\arctan(x-1) + C
C.arcsin⁡(x)+C\arcsin(x) + C
D.arcsin⁡(x−1)+C\arcsin(x-1) + C
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3

Evaluate the integral ∫1+xx dx\int \frac{\sqrt{1+\sqrt{x}}}{\sqrt{x}} \, dx.

A.23(1+x)3/2+C\frac{2}{3} (1+\sqrt{x})^{3/2} + C
B.43(1+x)3/2+C\frac{4}{3} (1+\sqrt{x})^{3/2} + C
C.43(1+x)3/2⋅1x+C\frac{4}{3} (1+\sqrt{x})^{3/2} \cdot \frac{1}{\sqrt{x}} + C
D.13(1+x)3/2+C\frac{1}{3} (1+\sqrt{x})^{3/2} + C
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