braindrill

Integration by Substitution

10 practice questionsAP Calculus ABStep-by-step solutions

Try a few

1

A particle moves along a line with velocity v(t)=tt2+1v(t) = t\sqrt{t^2+1} m/s. Find its displacement function s(t)=v(t)dts(t) = \int v(t)\,dt (indefinite integral).

A.12(t2+1)3/2+C\frac{1}{2}(t^2+1)^{3/2} + C
B.13t(t2+1)3/2+C\frac{1}{3}t(t^2+1)^{3/2} + C
C.23(t2+1)3/2+C\frac{2}{3}(t^2+1)^{3/2} + C
D.13(t2+1)3/2+C\frac{1}{3}(t^2+1)^{3/2} + C
🔒 Answer + full step-by-step solutionUnlock free →
2

Evaluate the indefinite integral: 2x+1x2+x+1dx\int \frac{2x+1}{\sqrt{x^2+x+1}} \, dx

A.x2+x+1+C\sqrt{x^2+x+1} + C
B.23(x2+x+1)3/2+C\frac{2}{3}(x^2+x+1)^{3/2} + C
C.12x2+x+1+C\frac{1}{2}\sqrt{x^2+x+1} + C
D.2x2+x+1+C2\sqrt{x^2+x+1} + C
🔒 Answer + full step-by-step solutionUnlock free →
3

The electric field along a line is proportional to x2+1x4+1\frac{x^2+1}{x^4+1}. Find its potential function (indefinite integral) x2+1x4+1dx\int \frac{x^2+1}{x^4+1} \, dx.

A.12lnx4+1+C\frac{1}{2} \ln|x^4+1| + C
B.12arctan(x2)+C\frac{1}{2} \arctan(x^2) + C
C.12arctan(x212x)+C\frac{1}{\sqrt{2}} \arctan\left(\frac{x^2-1}{\sqrt{2}\,x}\right) + C
D.12arctan(x22)+C\frac{1}{\sqrt{2}} \arctan\left(\frac{x^2}{\sqrt{2}}\right) + C
🔒 Answer + full step-by-step solutionUnlock free →

Master integration by substitutionnot just preview it

All 10 questions with worked solutions, an AI tutor that explains every step, and games that make the drilling stick. Free to start.

Practice this topic free

No card needed · 10 free AI questions daily