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Derivatives: Basic Rules

10 practice questionsAP Calculus ABStep-by-step solutions

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1

The position of a particle is given by s(t)=(t2+1)(2t3)3(t4+5)2s(t) = \frac{(t^2+1)(2t-3)^3}{(t^4+5)^2} meters. Find the velocity v(t)=s(t)v(t) = s'(t).

A.v(t)=(2t3)2(6t6+18t510t4+24t3+50t230t+30)(t4+5)3v(t) = \frac{(2t-3)^2(-6t^6+18t^5-10t^4+24t^3+50t^2-30t+30)}{(t^4+5)^3} meters per second
B.(2t3)2(10t26t+6)8t3(t4+5)\frac{(2t-3)^2(10t^2-6t+6)}{8t^3(t^4+5)}
C.(2t3)2(10t66t5+6t44t3+56t234t+36)(t4+5)3\frac{(2t-3)^2(10t^6-6t^5+6t^4-4t^3+56t^2-34t+36)}{(t^4+5)^3}
D.(2t3)2(9t6+18t513t4+24t3+35t230t+15)(t4+5)3\frac{(2t-3)^2(-9t^6+18t^5-13t^4+24t^3+35t^2-30t+15)}{(t^4+5)^3}
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2

The displacement of a particle is given by s(t)=t(t2+1)t3/2+1s(t) = \frac{\sqrt{t} \, (t^2 + 1)}{t^{3/2} + 1} meters, where tt is in seconds. Find the velocity v(t)=s(t)v(t) = s'(t) at t=4t = 4 seconds.

A.10712\frac{107}{12}
B.107108\frac{107}{108} m/s
C.274\frac{27}{4}
D.11
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3

The population of a bacteria colony is modeled by P(t)=(t2+3t)tt+2P(t) = \frac{(t^2 + 3t) \sqrt{t}}{t + 2} for t0t \geq 0 hours. Find the rate of change of the population at t=4t = 4 hours.

A.2929
B.593\frac{59}{3}
C.5918\frac{59}{18} bacteria per hour
D.296\frac{29}{6}
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