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Diagonalization

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1

The matrix A=(3126)A = \begin{pmatrix} 3 & 1 \\ -2 & 6 \end{pmatrix} is diagonalizable as A=PDP1A = PDP^{-1}. Taking the eigenvalues in increasing order on the diagonal, what is DD?

A.D=(4005)D = \begin{pmatrix} -4 & 0 \\ 0 & -5 \end{pmatrix}
B.D=(5006)D = \begin{pmatrix} 5 & 0 \\ 0 & 6 \end{pmatrix}
C.D=(5004)D = \begin{pmatrix} 5 & 0 \\ 0 & 4 \end{pmatrix}
D.D=(4005)D = \begin{pmatrix} 4 & 0 \\ 0 & 5 \end{pmatrix}
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2

The matrix A=(1071411)A = \begin{pmatrix} -10 & 7 \\ -14 & 11 \end{pmatrix} is diagonalizable as A=PDP1A = PDP^{-1}. Taking the eigenvalues in increasing order on the diagonal, what is DD?

A.D=(3004)D = \begin{pmatrix} -3 & 0 \\ 0 & 4 \end{pmatrix}
B.D=(4003)D = \begin{pmatrix} 4 & 0 \\ 0 & -3 \end{pmatrix}
C.D=(3004)D = \begin{pmatrix} 3 & 0 \\ 0 & -4 \end{pmatrix}
D.D=(2005)D = \begin{pmatrix} -2 & 0 \\ 0 & 5 \end{pmatrix}
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3

The matrix A=(2125)A = \begin{pmatrix} 2 & 1 \\ -2 & 5 \end{pmatrix} is diagonalizable as A=PDP1A = PDP^{-1}. Taking the eigenvalues in increasing order on the diagonal, what is DD?

A.D=(4005)D = \begin{pmatrix} 4 & 0 \\ 0 & 5 \end{pmatrix}
B.D=(4003)D = \begin{pmatrix} 4 & 0 \\ 0 & 3 \end{pmatrix}
C.D=(3004)D = \begin{pmatrix} 3 & 0 \\ 0 & 4 \end{pmatrix}
D.D=(3004)D = \begin{pmatrix} -3 & 0 \\ 0 & -4 \end{pmatrix}
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