Antiderivatives

The current in an AC circuit is given by $I(t) = \frac{1}{1+\cos t}$ amperes, where $t$ is time in seconds. The charge $Q(t)$ (in coulombs) is the antiderivative of the current, i.e., $Q(t) = \int I(t)\, dt$. Determine $Q(t)$ (include the constant of integration).

Find the general antiderivative: $\displaystyle\int \left(4 x^{4}\right)dx$.

Find the general antiderivative: $\displaystyle\int \left(4 x^{3} + x^{2}\right)dx$.