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Exponentials and Logarithms

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1

A bacterial culture starts with 1000 bacteria and doubles every 3 hours. Simultaneously, a disinfectant reduces the population by 20% every hour (i.e., the population is multiplied by 0.8 each hour). After how many hours does the net population reach 5000? Provide the exact answer in terms of natural logarithms.

A.t=3ln57ln23ln5t = \frac{3\ln 5}{7\ln 2 - 3\ln 5} hours
B.t=3ln57ln2+3ln5t = \frac{3\ln 5}{7\ln 2 + 3\ln 5}
C.t=3ln57ln2ln5t = \frac{3\ln 5}{7\ln 2 - \ln 5}
D.t=ln5ln1.6t = \frac{\ln 5}{\ln 1.6}
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2

The concentration of a certain drug in a patient's bloodstream (in mg/L) after tt hours is modeled by C(t)=e2t5et+6C(t) = e^{2t} - 5e^{t} + 6. At what times tt is the concentration zero? Solve for tt.

A.t=ln2t = \ln 2 and t=ln3t = \ln 3
B.t=0t = 0 and t=1t = 1
C.t=2t = 2 and t=3t = 3
D.t=ln5t = \ln 5 and t=ln6t = \ln 6
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3

Solve for xx: 32x+1=523x23^{2x+1} = 5 \cdot 2^{3x-2}

A.x=ln(12)ln(9/8)x = \frac{\ln(12)}{\ln(9/8)}
B.x=ln(5)2ln(2)ln(3)3ln(2)x = \frac{\ln(5) - 2\ln(2)}{\ln(3) - 3\ln(2)}
C.x=ln(512)ln(98)x = \frac{\ln\left(\frac{5}{12}\right)}{\ln\left(\frac{9}{8}\right)}
D.x=ln(15/4)ln(9/8)x = \frac{\ln(15/4)}{\ln(9/8)}
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